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Math · Two-Step Equations
Two-Step Equations: Undo in Reverse Order, Balance, Solve, Check
Build on one-step equations by undoing two operations in reverse order, preserving equality on both sides and checking each solution by substitution.
The idea
A two-step equation has two operations connected to the variable. Solving means undoing those operations until the variable stands alone.
Undo operations in reverse order. In 3x + 5 = 23, addition by 5 happened after multiplication by 3, so subtract 5 first and divide by 3 second.
Whatever operation you perform on one side of an equation must also be performed on the other side. A final substitution check catches many sign and order errors.
Worked examples
Example 1 · Multiply, then add
Solve 3x + 5 = 23.
- Subtract 5 from both sides: 3x = 18.
- Divide both sides by 3: x = 6.
- Check: 3(6) + 5 = 18 + 5 = 23.
x = 6.
Example 2 · Multiply, then subtract
Solve 4n − 7 = 21.
- Add 7 to both sides: 4n = 28.
- Divide both sides by 4: n = 7.
- Check: 4(7) − 7 = 28 − 7 = 21.
n = 7.
Example 3 · Divide, then add
Solve y ÷ 5 + 6 = 10.
- Subtract 6 from both sides: y ÷ 5 = 4.
- Multiply both sides by 5: y = 20.
- Check: 20 ÷ 5 + 6 = 4 + 6 = 10.
y = 20.
Example 4 · Divide, then subtract
Solve p ÷ 3 − 4 = 5.
- Add 4 to both sides: p ÷ 3 = 9.
- Multiply both sides by 3: p = 27.
- Check: 27 ÷ 3 − 4 = 9 − 4 = 5.
p = 27.
Example 5 · A negative solution
Solve 2a + 9 = 3.
- Subtract 9 from both sides: 2a = −6.
- Divide both sides by 2: a = −3.
- Check: 2(−3) + 9 = −6 + 9 = 3.
a = −3.
Example 6 · From a situation
Three identical notebooks plus a $4 folder cost $25. Solve 3c + 4 = 25.
- Subtract the fixed $4 first: 3c = 21.
- Divide by 3: c = 7.
- Check: 3($7) + $4 = $25.
Each notebook costs $7.
Common mistakes
These are tempting because they use familiar operations. Check what the question is actually measuring.
Why this fails: The +5 is the outer operation. Undo it first; otherwise every term must be divided carefully and the work becomes error-prone.
Why this fails: Equality is preserved only when the same operation is applied to both sides.
Why this fails: A term does not cross the equals sign and magically change sign; subtract or add the same amount on both sides.
Why this fails: After one step, the variable may still be multiplied or divided. Continue until it is isolated.
Why this fails: Replacing the variable with your answer verifies that the original left and right sides really match.
Foundation
Foundation practice
Solve two-step equations with positive whole-number solutions.
1. 2x + 3 = 15
2. 5a + 4 = 29
3. 3m − 2 = 19
4. 6n − 5 = 31
5. q ÷ 4 + 2 = 8
6. r ÷ 5 − 3 = 4
7. 7k + 1 = 36
8. 4t − 9 = 19
9. Does x = 8 solve 3x + 2 = 26?
10. In 5x + 7 = 32, which inverse operation should come first?
Core
Core practice
Mix structures and include zero or negative solutions.
11. 8x + 6 = 54
12. 9y − 11 = 34
13. 3a + 8 = 2
14. 4b − 12 = −12
15. c ÷ 6 + 5 = 9
16. d ÷ 7 − 2 = 6
17. 2p − 15 = −5
18. 5q + 12 = 7
19. A student solves 4x + 3 = 27 by dividing 27 by 4 first. What should happen first?
20. Does n = −3 solve 2n + 10 = 4?
Reasoning
Reasoning practice
Translate short situations into equations, then solve and check.
21. A $5 fee plus 3 equal tickets costs $26. What is each ticket price?
22. Four equal bags plus 2 loose apples make 30 apples. How many apples are in each bag?
23. A number is multiplied by 6 and then decreased by 8 to make 40. Find the number.
24. A number divided by 4, then increased by 3, equals 10. Find the number.
25. Which equation matches: twice a number, plus 9, is 25?
26. Which equation matches: one fifth of a number, minus 2, is 6?
27. If 3x + 4 = 19, what is 3x before solving for x?
28. If y ÷ 8 − 1 = 4, what is y ÷ 8 before solving for y?
29. Why is substitution useful after solving?
30. If you subtract 6 from the left side of an equation while solving, what must you do to the right side?
Stretch
Stretch practice
Handle larger values, negatives and missing-step reasoning.
31. 12x + 17 = 101
32. 15m − 28 = 62
33. 7n + 20 = −1
34. 5p − 6 = −31
35. q ÷ 9 + 7 = 12
36. r ÷ 12 − 4 = 3
37. 4x + 9 = 41 → 4x = 32. What operation produced the second equation?
38. 6y − 5 = 43 → 6y = 48. What operation produced the second equation?
39. A student says x = 4 solves 5x + 8 = 33. Is the student correct?
40. Why do we say to undo operations in reverse order?
Answer key
- 1. x = 6
Subtract 3: 2x = 12. Divide by 2. - 2. a = 5
Subtract 4: 5a = 25. Divide by 5. - 3. m = 7
Add 2: 3m = 21. Divide by 3. - 4. n = 6
Add 5: 6n = 36. Divide by 6. - 5. q = 24
Subtract 2: q ÷ 4 = 6. Multiply by 4. - 6. r = 35
Add 3: r ÷ 5 = 7. Multiply by 5. - 7. k = 5
Subtract 1: 7k = 35. Divide by 7. - 8. t = 7
Add 9: 4t = 28. Divide by 4. - 9. Yes
3(8) + 2 = 24 + 2 = 26. - 10. Subtract 7 from both sides.
The addition of 7 is the outer operation, so undo it first. - 11. x = 6
Subtract 6 to get 8x = 48, then divide by 8. - 12. y = 5
Add 11 to get 9y = 45, then divide by 9. - 13. a = −2
Subtract 8: 3a = −6. Divide by 3. - 14. b = 0
Add 12: 4b = 0. Divide by 4. - 15. c = 24
Subtract 5: c ÷ 6 = 4. Multiply by 6. - 16. d = 56
Add 2: d ÷ 7 = 8. Multiply by 7. - 17. p = 5
Add 15: 2p = 10. Divide by 2. - 18. q = −1
Subtract 12: 5q = −5. Divide by 5. - 19. Subtract 3 from both sides.
Undo the outer +3 before undoing multiplication by 4. - 20. Yes
2(−3) + 10 = −6 + 10 = 4. - 21. $7
3t + 5 = 26. Subtract 5, then divide by 3. - 22. 7 apples
4b + 2 = 30. Subtract 2, then divide by 4. - 23. 8
6x − 8 = 40. Add 8, then divide by 6. - 24. 28
x ÷ 4 + 3 = 10. Subtract 3, then multiply by 4. - 25. 2x + 9 = 25
Twice a number is 2x; then add 9 and set it equal to 25. - 26. x ÷ 5 − 2 = 6
One fifth of x is x ÷ 5; then subtract 2. - 27. 15
Subtract 4 from both sides first. - 28. 5
Add 1 to both sides first. - 29. It checks whether the solution makes the original equation true.
A correct solution gives equal values on both sides of the original equation. - 30. Subtract 6 from the right side too.
Applying the same operation to both sides preserves equality. - 31. x = 7
Subtract 17: 12x = 84. Divide by 12. - 32. m = 6
Add 28: 15m = 90. Divide by 15. - 33. n = −3
Subtract 20: 7n = −21. Divide by 7. - 34. p = −5
Add 6: 5p = −25. Divide by 5. - 35. q = 45
Subtract 7: q ÷ 9 = 5. Multiply by 9. - 36. r = 84
Add 4: r ÷ 12 = 7. Multiply by 12. - 37. Subtract 9 from both sides.
Subtracting 9 cancels +9 and changes 41 to 32. - 38. Add 5 to both sides.
Adding 5 cancels −5 and changes 43 to 48. - 39. No; x = 5.
5(4) + 8 = 28, not 33. Solving gives 5x = 25, so x = 5. - 40. Because the outermost or most recent operation must be removed before the earlier operation on the variable can be undone cleanly.
For ax + b = c, undo +b first, then undo multiplication by a.